0=x^2-100x+2125

Solution for 0=x^2-100x+2125 equation:

0=x^2-100x+2125

We move all terms to the left:

0-(x^2-100x+2125)=0

We add all the numbers together, and all the variables

-(x^2-100x+2125)=0

We get rid of parentheses

-x^2+100x-2125=0

We add all the numbers together, and all the variables

-1x^2+100x-2125=0

a = -1; b = 100; c = -2125;
Δ = b2-4ac
Δ = 1002-4·(-1)·(-2125)
Δ = 1500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1500}=\sqrt{100*15}=\sqrt{100}*\sqrt{15}=10\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-10\sqrt{15}}{2*-1}=\frac{-100-10\sqrt{15}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+10\sqrt{15}}{2*-1}=\frac{-100+10\sqrt{15}}{-2}
$